(x^2+5x+8/x+3)+(x^2+x-3/x-2)=2x+5

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Solution for (x^2+5x+8/x+3)+(x^2+x-3/x-2)=2x+5 equation: 



(x^2+5x+8/x+3)+(x^2+x-3/x-2)=2x+5

We move all terms to the left:

(x^2+5x+8/x+3)+(x^2+x-3/x-2)-(2x+5)=0



Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x-2)!=0

x∈R



We get rid of parentheses

x^2+x^2+5x+8/x+x-3/x-2x+3-2-5=0

We multiply all the terms by the denominator


x^2*x+x^2*x+5x*x+x*x-2x*x+3*x-2*x-5*x+8-3=0

We add all the numbers together, and all the variables

x^2*x+x^2*x-4x+5x*x+x*x-2x*x+5=0

Wy multiply elements

x^3+x^3+5x^2+x^2-2x^2-4x+5=0

We do not support expression: x^3

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